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II.1.6.3 Out-of-plane shear stress partial derivative equations

Note that the global equilibrium equation (II.1.36) and (II.1.37) do not contain the components Mxx,y and Myy,x of the bending moments tensor. Similarly, the local equilibrium equations do not contain the components σxx,y and σyy,x of the Cauchy stress tensor. Then, these components can be considered as zero without modifying the result of the developments. The corresponding lines and columns could be removed from the equations (II.1.39).

In fact, one can do better than that. The local equilibrium equations (II.1.34) and (II.1.35) are rewritten as follows:

{ τxz,z(z) τyz,z(z) } lam = [ - 10 00 0 - 1 0 0 - 1 0 - 1 0 ]⋅ {σxx,x(z) σyy,x(z) τxy,x(z) σxx,y(z) σyy,y(z) τxy,y(z) } lam.
(II.1.40)

The substitution of (II.1.39) in (II.1.40) leads to the following expression:

{ τxz,z(z) τyz,z(z) } lam = [ - 10 00 0 - 1 0 0 - 1 0 - 1 0 ] ⋅ [ [F ]lam(z) 000 0 0 0 000 000 0 0 0 000 [F ]lam(z) ] ⋅ {Mxx,x Myy,x Mxy,x Mxx,y Myy,y Mxy,y } lam.(II.1.41)

This yields a new expression of the relation between bending moment gradients and out-of-plane shear stress. A new matrix is first calculated as follows:

[J ]lam(z) = - [100001 0 0 1 0 1 0 ]⋅ [ [F ]lam(z) 000 0 0 0 000 000 0 0 0 000 [F ]lam(z) ] .

[J ]lam(z) is a 2 × 6 matrix that relates the out-of-plane shear stress component partial derivatives with respect to z to the in-plane bending moment components:

{ τxz,z(z) τyz,z(z) } lam = [J ]lam(z)⋅ {Mxx,x Myy,x Mxy,x Mxx,y Myy,y Mxy,y } lam.
(II.1.42)

The matrix [J ]lam(z) depends on z for two reasons: because of the triangular distribution of strains through the thickness, and because material moduli depend on plies material and orientation. In a given ply of index k, one has:

[Jk] lam(z) = [J0k] lam + z [J1k] lam,

in which the components of the two matrices [J0k] lam and [J1k] lam are constant. Similarly, one can write a polynomial expression for [F ]lam(z) if one splits the definition by plies:

[Fk] lam(z) = [Ck] lam ⋅ ( [b]lam + z [d]lam) , = ( [Ck] lam ⋅ [b]lam) + ( [Ck] lam ⋅ [d]lam) z, = [F0k] lam + [F1k] lamz.

The following two relations hold:

[J0k] lam = - [P1]⋅ [ [F0k] lam 000 0 0 0 000 000 0 0 0 000 [F0k] lam ] ,

[J1k] lam = - [P1]⋅ [ [F1k] lam 000 0 0 0 000 000 0 0 0 000 [F1k] lam ] .